Question

the brakes applied to ka produces an acceleration of 6 metre per second per second square in the opposite direction to the motion of the Earth takes to second stop after the application of brakes calculate the distance travelled during this velocity​

Answer 1

Answer:

Acceleration a = -6 m/s^2

Time t = 2 s

Final velocity v = 0 m/s

Let initial velocity be u

Let distance be s

v = u + at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2

So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m

Thus, distance travelled is 12 m

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Explanation:

Answer 2

Answer:

the big replied to car produce an acceleration of 6 metre per second square in opposite direction to the motion of the Earth takes to second stop