The brakes are applied to a car and the car stops in 2 seconds after travelling a distance of 12 m calculate the retardation if the car was moving with a velocity of 60 M per second
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s=ut+1/2at^
12=60×2+1/2a2^solve this get the answer
12=60×2+1/2a2^solve this get the answer
rahulpanwar931p9nhja:
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Answered by
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v²=u²+2as
where v is final velocity
t= time taken
a= acceleration
s= displacement
u= initial velocity
putting these values
we get
0=(60)²+2*a*12
or a=-3600/24= -150m/s²
retardation=150m/s2
where v is final velocity
t= time taken
a= acceleration
s= displacement
u= initial velocity
putting these values
we get
0=(60)²+2*a*12
or a=-3600/24= -150m/s²
retardation=150m/s2
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