Question

The brakes are applied to a car moving with velocity of 12 m/s. It produce an acceleration of 6 ms-2in the opposite direction to the motion. If the car takes 2s to stop after the application of brakes, calculate the distance it travels during this time.

Answer 1

Here,

• u = 12 m/s

• acceleration = -6 m/s² ( since it is in opposite direction )

• time taken to stop = 2 sec

using 2nd equation of motion ,

=> s = ut + 1/2 at²......

where, s = displacement

=> s = 12×2 + 1/2 (-6)(2)²

=> s = 24 - 12 = 12 m

[==> Distance traveled = 12 m ]