the brakes are applied to a car produce an acceleration of 6/s² in the opposite direction to the motion if the car takes 2sec to stop after the application of brakes ,calculate the distance it travels during this time?
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a=v-u/t
u=12
s=ut+1/2at²
s=12*2+1/2*6*2²
s=24+12
s=36m
u=12
s=ut+1/2at²
s=12*2+1/2*6*2²
s=24+12
s=36m
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