Question

The brakes are applied to a car to produce an acceleration of 12 ms-2 in the opposite direction of motion. If the car takes 4 seconds to stop, calculate the distance travelled by the car in this time interval.

answer it first and make points​

Answer 1

Answer:

Explanation:

Acceleration a = -12 m/s^2

Time t = 4 s

Final velocity v = 0 m/s

Let initial velocity be u

Let distance be s

v = u + at

So, 0 = u + (-12)(4)

So, u = 48 m/s

Now, s = ut + (1/2) at^2

So, s = 48(2) + (1/2)(-12)(4^2)

So, s = 96+(-6)(16)

So, s = 96-96 m

So, s=0m

Thus, distance travelled is 0 m