Question

The brakes are applied to a train moving at 36 km/h produce a retardation of 5m/s. what distance will it cover before coming to a stop ?​

Answer 1

Explanation:

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Answer 2

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u = 36 km/h = 10 m/s 

v =0

t = 5 s 

  i) v = u + at  0 = 10 + a x 5 

Thus,  a = -10/5  a = 2 m/s2  Thus, retardation of the car is 2 m/s2   

ii)  s = ut + 1/2 at2  s = 10 x 5 + (1/2) x (-2) x 52  s = 50 - 25 = 25 m