The brakes of a 1000 kg car exert a force of 3000 N.How long will it take the car to stop from a velocity of 30m/s
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Answered by
16
the time will be 10 sec
Answered by
45
10 seconds F=ma ;a =(v-u)/t put the values in the equation
3000=1000x(30-0)/t by cross multiplication t=30000/3000=10seconds
3000=1000x(30-0)/t by cross multiplication t=30000/3000=10seconds
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