The brakes of a train produce a retardation of 0.1 m/s. If it's moving at 20m/s how far will it travel before it stops?
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Answer:Acceleration due to friction (retardation) (a) = - μg=−0.9×10=−9m/s
2
Final velocity, v=0m/s
Initial velocity, u=20m/s
Applying formula: v
2
=u
2
+2as
Where s is the distance traveled by car before it come to rest.
⇒0
2
=20
2
+2(−9)s
⇒18s=400
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