Computer Science, asked by ashokrai7171, 1 month ago

The branch of the table 'STATIONARY' Given below 80 12 Dinal 3 14 Then no Tem nami. linit Price Quantity Ben 40 5 90 Exex 3 15 Shaqanix 5 10 15 20 50 suggest suitable data type and size of each column Column Name Type Size em nami unit pa Quantity​

Answers

Answered by sipraacharjer
0

Explanation:

(a) 10y=80

y=10 is not a solution to the given equation because for y=10,10y=10×100, and not 80

(b) 10y=80

y=8 is a solution to the given equation because for y=8,10y=10×8=80 and hence, the equation is satisfied.

(c) 10y=80

y=S is not a solution to the given equation because for y=5,10y=10×5=50, and not 80

(d) 4l=20

l=20 is not a solution to the given equation because for l=20,4l=4×20=80, and not 20

(e) 4l=20

I=80 is not a solution to the given equation because for /=80,4l=4×80=320, and not 20

(f) 4l=20

l=5 is a solution to the given equation because for I=54l=4×5=20 and hence, the equation is satisfied.

(g) b+5=9

b=5 iS not a solution to the given equation because for b=5,b+5=5+5=10, and not 9

(h) b+5=9

b=9 is not a solution to the given equation because for b=9,b+5=5+5=10, and not 9

(i) b+5=9

B=4 is a solution to the given equation because for b=4,b+5=4+5=9 and hence, the equation is satisfied.

(j) h−8=5

h=13 is a solution to the given equation because for h=13,H−8=13−8=5 and hence, the equation is satisfied.

(k) h−8=5

h=8 is not a solution to the given equation because for h=8,H−8=8−8=0, and not 5

(l) h−8=5

h=0 is not a solution to the given equation because for h=0,H−8=0−8=−8, and not 5

(m) p+3=1

p=3 is not a solution to the given equation because for p=3,p+3=3+3=6, and not 1

(n) p+3=1

p=1 is not a solution to the given equation because for p=3,p+3=1+3=4, and not 1

(o) p+3=1

p=0 is not a solution to the given equation because for p=0,p+3=0+3=4, and not 1

(p) p+3=1

p=−1 is not a solution to the given equation because for p=−1,p+3=−1+3=4, and not 1

(q) p+3=1

p=−2 is a solution to the given equation because for p=−2,p+3=−2+3=1 and hence, the equation is satisfied.

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