Question

the breadth and perimeter of rectangle whose area is 47 and length is 15 metres

Answer 1

Answer:

Area of the rectangle = 47m^2

L×B = 47

15×B = 47

B = 47/15

B = 3.1333m^2

Perimeter of the rectangle= 2(L+B)

= 2× 50.1333/10000

= 2× 501333/10000

= 100.2666m

Answer 2

AnSwer :

⌬ Area of rectangle = 47 m²

⌬ Length of rectangle = 15 m

⌬ Breadth of rectangle = ?

⌬ Perimeter of rectangle = ?

• As per question we are provided with the length of the rectangle and area of rectangle and we need to find the perimeter of rectangle and also breadth of rectangle. So, first we will find the breadth of rectangle by assuming it as 'b' and just simply we have to put this in the formula of area of rectangle and hence we will find the breadth of rectangle and after that we will find the perimeter of rectangle. So, let's start :

◖According to the Question Now◗

⇢Area of rectangle = Length × Breadth

⇢47 = 15 × b

⇢b = 47 ÷ 15

⇢b ≈ 3.14 m

∴ Breadth of the given rectangle is 3.14 cm .

᠂ PERIMETER OF RECTANGLE :

↛Perimeter of rectangle = 2(Length + Breadth)

↛Perimeter of rectangle = 2(15 + 3.14)

↛Perimeter of rectangle = 2(18.14)

↛Perimeter of rectangle = 36.28 m

∴ The Perimeter of rectangle is 36.28 m.