The breadth of a rectangle is 3 cm less than its length. If the area of the rectangle is 88cm square ,find its perimeter.
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I-b=3, Ixb=88
(I +b) 2-(1-b) 2 = 4 Ib
(I +b) 2-9=352
(I +b) 2 = 36l
I+b=v361=19
I-b=3, solving
I=11, b = 8
perimeter 2 (I +b) = 39 cm
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