Question

the breadth of a rectangle is 5 more than one - third of the length the perimeter of the rectangle is 42 cm find the
length of the rectangle
​

Answer 1

Step-by-step explanation:

Let the length of the rectangle be y and the width be x.

From the information we have :

x = 1/3y + 5

making y the subject of the equation we have :

1/3y = x - 5

y = (x - 5)3

y = 3x - 15

The perimeter from the dimensions is :

2x +2(3x - 15) = 42

2x + 6x - 30 = 42

8x = 72

x = 9

The length will be :

(3 × 9 - 15) = 12 cm

Width is 9cm

Answer 2

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Let the length of rectangle be x

Then breadth = x/3 + 5 = (x + 15)/3

Pπ of rectangle = 2(l+ b)

=>42cm = 2[x + (x+15)/3]

=>42cm = 2[(3x + x + 15)/3]

=>42cm = 2[(4x + 15)/3]

=>42cm = (8x + 30)/3

=>([42 × 3 - 30]/8)cm = x

=>(86 - 30)/8 cm = x

=>56/8 cm = x

=>x = 7cm

• Therefore, the length of the rectangle is 7cm.

$\rule{200pt}{5pt}$