Question

The breadth of a rectangle is 6cm and each of its diagonals mesasure 10cm find its length?​

Answer 1

$\huge{\mathfrak{\underline{Answer :-}}}$

$\huge{\mathfrak{\boxed{\underline{\sf Length \: = 8 \: cm}}}}$

$\bf\huge\underline{Explanation :-}$

Given :

Breadth of rectangle - 6 cm

Length of the diagonal - 10 cm

To find :

The length of rectangle

Solution :

We know that,

$\sf Diagonal = \sqrt{ {l}^{2} + {b}^{2} }$

$\sf\longrightarrow Diagonal = 10 cm$

$\sf\longrightarrow \sqrt{ {l}^{2} + {6}^{2} }$

$\sf\longrightarrow \sqrt{ {l}^{2} + 36}$

$\sf\longrightarrow {l}^{2} + 36 = {10}^{2}$

$\sf\longrightarrow {l}^{2} + 36 = 100$

$\sf\longrightarrow {l}^{2} = 100 - 36$

$\sf\longrightarrow {l}^{2}$

$\sf\longrightarrow l = \sqrt {64}$

$\sf\therefore l = 8∴l=8$

The length of the rectangle is 8 cm respectively