Question

The breadth of a rectangle is 'b'. Its length is 3 cm more than its breadth. and the length of one of its diagonal is 5b +6.

Subtract the diagonal from area of rectangle?

Answer 1

given that :

breadth     = b

length        =  b+3

diagonal     =   5b+6

 

=  $\frac{b(b+3)}{2}$

= $b^2+3b -(5b+6)$

=$b^2-2b-6$

I hope this is the answer

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