Question

The breadth of a rectangle whose area is 110 sq cm and length is 11 cm .​

Answer 1

Answer:

10cm

Step-by-step explanation:

area of rectangle - l×b

110 - 11× x

x - 110÷11

x- 10

Answer 2

$\large\sf\underline{Given\::}$

• Area of the rectangle = 110 sq. cm

• Length of the rectangle = 11 cm

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$\large\sf\underline{To\:find\::}$

• Breadth of the rectangle

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$\large\sf\underline{Concept\::}$

Here we are given the area of the rectangle as 110 sq. cm and also the length as 11 cm. We are asked to find the breadth of the rectangle. So we are gonna frame an equation using the formula for area of rectangle and the given value of area . After framing and solving appropriate equation we will get the required value of breadth of the rectangle.

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$\large\sf\underline{Formula\:to\:be\:used\::}$

$\large{\mathfrak\orange{Area\:of\:the\:rectangle\:=\: l \times b}}$

where :

• l stands for $\tt\blue{Length}$

• b stands for $\tt\blue{breadth}$

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$\large\sf\underline{Solution\::}$

So let's frame an equation :

$\sf\:Area\:of\:the\:rectangle\:=110$

• Substituting the formula

$\sf\implies\:length \times breadth\:=110$

• Substituting the given value for length

$\sf\implies\:11 \times breadth\:=110$

• Transposing 11 to the other side it goes to the denominator

$\sf\implies\:breadth\:=\frac{110}{11}$

• Reducing the fraction in lower terms

$\sf\implies\:breadth\:=\cancel{\frac{110}{11}}$

$\small{\underline{\boxed{\mathrm\red{\implies\:Breadth\:=\:10\:cm}}}}$ ★

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$\large\sf\underline{Verifying\::}$

Not sure about the ansWers !? Let's verify it once

For verifying we will simply plug the value we got, in the equation that we had formed earlier. Doing so if we get LHS = RHS, our answers would be correct.

$\sf\leadsto\:length \times breadth\:=110$

• Substituting the values

$\sf\leadsto\:11 \times 10\:=110$

$\sf\leadsto\:110\:=110$

$\bf\leadsto\:LHS\:=\:RHS$

$\large{\mathfrak{hence\:verified\:!!}}$

____________________‎

$\dag\:\underline{\sf So\:the\:required\:breadth\:is\:10\:cm}$ .

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!! Hope it helps !!