Question

the breadth of a rectanglular garden is 2/3 of its length. if its perimeter is 40m find its dimensions​

Answer 1

Answer:

$\sf \: let \: length \: be \: x \: m \\ \sf \: therefore \: breadth = \frac{2}{3} m \\ \\ \sf \: acq \\ \\ \sf \: 2(l + b) = 40 \\ \sf \: \frac{2x}{3} + x = 20 \\ \\ \sf \: 2x + 3x = 60 \\ \\ \sf x = 12m \\ \\ \underline{ \huge{ \boxed{ \red{ \sf \: length = 12m}}}} \\ \\ \\ \underline{ \huge{ \boxed{ \purple{ \sf \: breadth = \frac{2}{3} \times 12 = 8m}}}}$

Answer 2

Step-by-step explanation:

length be x m

breadth = 2/3 of length

= 2/3 ×x

= 2x/3

perimeter of rectangle = 2 (l+b)

40 m = 2( x + 2x/3)

40 / 2 m = x + 2x/3

20m = 3x + 2x /3

20 m = 5x /3 m

20 ×3/5 = x

4 ×3 = x

12m = x

length = 12 m

breadth 2/3 × 12

= 2 ×4 m

8 m