Question

the breadth of a rectangular court is 6m less than its length and it's perimeter is 68m. find the area of rectangular court.
please, help!

Answer 1

let the length of the court is x

then the breadth will be x-6

perimeter of a rectangle is 2(l+b)

a.q. 2{x+(x-6m)}=68m

= 2(x+x-6m)=68m

= 2(2x-6m)= 68m

=4x-12m=68m

=4x= 68m+12m

= 4x= 80m

=x= 80m/4

=x= 20m

l=20m

b=20m-6m=14m

area= lb

= 20m×14m= 280m^2

Answer 2

$\textbf{\underline{\underline{Answer :-}}}$

The area of the Rectangle is 280 sq.m

$\textbf{\underline{\underline{Explanation :- }}}$

$\textsf{\underline{\underline{Given :}}}$

The Perimeter = 68 m

Breadth = 6m less than its length

$\textsf{\underline{\underline{To find :}}}$

The area of the Rectangle

$\textsf{\underline{\underline{Solution :}}}$

$\textsf{Consider the Length as x}$

$\textsf{So, Breadth = x - 6}$

★ We know that : $\boxed{\sf{Perimeter = 2(Length + Breadth)}}$

$\sf{\implies}2(x + x - 6) = 68$

$\sf{\implies}2x + 2x - 12 = 68$

$\sf{\implies}4x - 12 = 68$

$\sf{\implies}4x = 68 + 12$

$\sf{\implies}4x = 80$

$\sf{\implies}x = \dfrac{80}{4}$

$\sf{\implies}x = 20$

$\textsf{Length of the Rectangle = 20 m}$

Value of x - 6

$\sf{\implies}$ 20 - 6

$\sf{\implies}$ 14

$\textsf{Length = 20 m}$

$\textsf{Breadth = 14 m}$

$\star$ Area of Rectangle

★ We know that : $\boxed{\sf{Area = Length \times Breadth}}$

$\sf{\implies}20 \times 14$

$\sf{\implies}280$

$\textsf{Area = 280 sq.m}$

$\therefore$ The area of the Rectangle is 280 sq.m