Physics, asked by navinpant123, 1 year ago

The breadth of an iron door is 2.4 m If the minimum torque required to open the door is 50
Nm. What is the minimum force needed to open the door.

Answers

Answered by shahbaja065

7

Explanation:

b = 2. 4 m , perpendicular distance = 50 Nm , moment of force = b × d , 2.4 × 50 = 12. 00 or 12.

Answered by vrudhishah2009

2

Answer:

20.8N

Explanation:

50Nm/2.4= 20.8Nm

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