Question

the breadth of rectangle garden is 2/3 of its length, it perimeter is 40 cm find it's dimension
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Answer 1

Given :-

• The breadth of rectangle garden is 2/3 of its length, it perimeter is 40 cm

To find :-

• Dimensions of rectangle

Solution :-

Let the length of rectangle is x then its breadth be 2x/3

• Perimeter of rectangle = 40m

As we know that

→ Perimeter of rectangle = 2(l + b)

Where " l " is length and " b " is breadth of rectangle

As per given condition

→ Perimeter of rectangle = 40m

→ 2(l + b) = 40

→ 2(x + 2x/3) = 40

→ x + 2x/3 = 40/2

→ 3x + 2x/3 = 20

→ 5x/3 = 20

→ 5x = 3 × 20

→ x = 3 × 20/5

→ x = 3 × 4

→ x = 12

Hence,

• Dimensions of rectangle
• Length of rectangle = x = 12m
• Breadth of rectangle = 2x/3 = 2*12/3 = 8m

Answer 2

Given:

• Breadth= 2/3 of Length
• Perimeter = 40cm

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Need to Find :

• Length=?
• Breadth =?

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Solution:

Let length= Y

then breadth= 2Y/3 (From the given information)

We know Perimeter of rectangle= 2×(length+ breadth)

⟹ Perimeter = $2 \times (y + \dfrac{2y}{3} )$

$\implies \: 40m \: = 2 \times (\dfrac{3y + 2y}{3} )$

$\implies \: 20m \: = \dfrac{5y}{3}$

$\implies \: y = \dfrac{20 \times 3}{5} m$

$\implies \: y = 12m$

• $\red{\bold{\therefore length=12m}}$

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Breadth = 2y/3

⟹ Breadth = (2×12)/3m

⟹ Breadth =2×4m

⟹Breadth= 8m

• $\red{\bold{\therefore breadth=8m}}$