Question

The breadth of rectangle is 2 less than one third of length of the rectangle. Find area if its perimeter is 260 m. please answer in detail

Answer 1

Let the length of the rectangle be x

Thus,breadth of the rectangle=1/3x-2

Perimeter=260m

2(l+b)=260

2(x+1/3x-2)=260

2x+2/3x-4=260

2x+2/3x=264

6x+2x/3=264

8x=792

x=792/8

x=99

Thus,length if the rectangle is 99m

Breadth=1/3×99-2=31m

Hence,area of the rectangle=l×b

99×31

3069m²

Thus,area of the rectangle is 3069m²

Answer 2

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☞ Area = 3369 m²

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$\huge\sf\blue{Given}$

✭ Breadth of a rectangle is 2 less than one third of length of one rectangle

✭ Perimeter = 260 m

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$\huge\sf\gray{To \:Find}$

◈ Its Area?

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