The breadth of rectangle is 3 less than the length if both length and breadth the reduced by 3 units the area of rectangle reduces by 176 square units find the dimensions of the original rectangle.
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Answers
HEY THERE!!!
Question:-
The breadth of rectangle is 3 less than the length if both length and breadth the reduced by 3 units the area of rectangle reduces by 176 square units find the dimensions of the original rectangle.
Solution:-
Let to Be Length of Rectangle = x
•°• Area of Rectangle = Length ×Breadth
As per as Question:-
Breadth of rectangle is 3 less than the length;
=) x-3
Now,
if both length and breadth the reduced by 3 units;-
Length= x-3
Breadth= x-3-3
•°• Breadth of rectangle= x-6
According to the Question;-
the area of rectangle reduces by 176 square ;-.
•°• Area of Rectangle = Length ×Breadth
Area of Rectangle= (x-3)(x-6)
x(x-3) -176=x(x-6)-3(x-6)
x²-3x -176=x²-6x-3x+18
x²-3x -176=x²-9x+18
-3x+9x=18+176
6x=294
x=194/6
•°• x=97/3
Here,Length of Rectangle= 97/3 metres
Considering on Breadth of rectangle;-
Breadth= x-3
•°• Substitute the value of length in breadth Equation;-
Breadth=x-3
Breadth=97/3-3
Breadth=97/3-3/1
•°• Breadth= 97-9/3
Breadth=88/3 meters
Hence,Dimensions of the original rectangle=
Length of Rectangle=97/3 metres
Breadth of rectangle=88/3 metres
Thank you!!!
then it's breadth = x-3
area = x(x-3)
if it's length and breadth are reduced by 3
then length = x-3
and breadth = x-3-3
=x-6
_________________
then it's area = x-3(x-6)
= x^2-6x-3x+18
=x^2-9x+ 18 = x(x-3)- 176
as the new area is 176 less than the previous one as described in question.
x= 194÷6
= 97/3...
breadth= 97/3- 3
= 97-9/3= 88/3
but if area got reduced by 174 instead of 176 sq.units
then
length = 32
and breadth = 35 .....
i think it's best answer and correct also
I'm sure please mark it as brainlist.