The breadth of rectangle is 5 less than one third of it's length .Find its dimensions ,if the perimeter is 142 cm
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BlackVenom05
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Let's assume the breadth as x meters
So, the length as (x + 5) meters
According to Question,
Perimeter of Rectangular plot = 142m
2(length + breadth) = 142 m
⇒ 2(x + 5 + x) = 142
⇒ 2x + 5 = 142 / 2
⇒ 2x + 5 = 71
⇒ 2x = 71 - 5
⇒ 2x = 66
⇒ x = 66 / 2
⇒ x = 33
Required Measurements -
Breadth = x = 33 m
Length = x + 5 = 33 + 5 = 38 m
Hence, the length and breadth of the rectangular plot are 38 meters and 33 meters respectively
Answer :
- Length of rectangle is 57cm
- Breadth of rectangle is 14cm
Given :
- The breadth of rectangle is 5 less than one third of its length
- Perimeter is 142cm
To find :
- Dimensions
Solution :
- Let the length of rectangle be x
The breadth of rectangle is 5 less than one third of its length so,
- Breadth of rectangle = 1/3x - 5
Perimeter = 142cm
As we know that,
- Perimeter of rectangle = 2(l + b)
Where, l is length and b is breadth
》Perimeter of rectangle = 2(l + b)
》142 = 2(x + 1/3x - 5)
》142/2 = 3x + x - 15 / 3
》71 = 4x - 15 / 3
》4x - 15 / 3 = 71
》4x - 15 = 71 × 3
》4x - 15 = 213
》4x = 213 + 15
》4x = 228
》x = 228/4
》x = 57cm
- Length of rectangle is 57cm
- Breadth of rectangle = 1/3x - 5 = 1/3(57) - 5 = 1/3 × 57 - 5 = 19 - 5 = 14cm