Question

The break applied to a car it produce an acceleration of 10m/s×s. If the car takes 5second to stop after applying the break calculate the distance covered by the car before coming to rest?

Answer 1

Hey friend

here is your answer

acceleration ( a ) = -10 m/ s×s
time ( t ) = 5 sec
initial velocity ( u ) = ?
final velocity ( v ) =0 m/sec
displacement ( s ) = ? ( to find )

as
$a = \frac{v - u}{t} \\ - 10 = \frac{0 - u}{5} \\ u = 50m {sec}^{ - 1}$
now
finding displacement

${v}^{2} = {u}^{2} - 2 \times s \\ 0 = 2500 - 2 \times s \\ s = 1250 \: metre$


glad to help you
hope it helps
thank you.