The break applied to a car produce a acceleration of 6m/s² in the opposite direction of the motion.if the cars takes 2 sec to stop after the application of breaks, calculate the distance traveled at this time and initial velocity
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Answer: 12 and 12 m/s
Explanation: v = 0
a = -6 m/s²
t = 2 sec.
v = u + at
=> u = v - at = -(-6) × 2 = 12 m/s( Ans.)
S = (v² - u²)/2a
= (0 - 144)/2×(-6)
= -144/-12 = 12 m ( Ans. )
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