Question

the break applied to a car produce an acceleration of 6 ms² in the opposite direction of the motion. if the car takes 2s to stop after the application of break . calculate the distance if traveled during this time​

Answer 1

Explanation:

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Answer 2

Answer:

Given:

Accerleration: a=−6 m/s2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+21at2

s=12×2+21×(−6)×4

⇒s=12 m