Question

The break applied to a car produce an acceleration of 6ms square in the opposite direction to the motion if the car takes 2s to stop after the application of beaks , calculate the distance it travel during this time

Answer 1

initial velocity u =v-at =0-(-6)×2 =12 m/s
distance traveled s = (v²-u²)/2a
s=(0-144)/(2×-6)
s = 144/12
s = 12 m

Answer 2

Hi friend,

V=u+at

U= v-at
U= 0-(-6)2

U=12m/s


Distance = velocity × time

Distance = 12×2

Distance = 24m.

Hope this helped you a little!!!