the break applied to the car produc an acceleration 66 km/h in opposite clirection in motion . if car take 3s for come in rest after the application break calculates. 1) the initial velocity of before applying brakes. 2) the distance covered by before stopping.
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Answer:
Explanation:
just apply the formula:V=U-at
where u=initial velocity and a=acceleration
here a is taken as negative because it is retarded....V is taken as 0 because the car is stopped.....
so after calculating, u=at
or, u=66*3.....
for distance use the formula;
s=ut+(1/2)at^2
take a negative
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