Question

the break applied to the car produc an acceleration 66 km/h in opposite clirection in motion . if car take 3s for come in rest after the application break calculates. 1) the initial velocity of before applying brakes. 2) the distance covered by before stopping.​

Answer 1

Answer:

Explanation:

just apply the formula:V=U-at

where u=initial velocity and a=acceleration

here a is taken as negative because it is retarded....V is taken as 0 because the car is stopped.....

so after calculating, u=at

or, u=66*3.....

for distance use the formula;

s=ut+(1/2)at^2

take a negative