Question

the break applief to a car produce an accelaration of 6m/s square in opposite direction to the motion. if the car takes 2s to stop after the application of break calculate the distance to travel this time​

Answer 1

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Answer 2

Answer:

Given:

Accerleration: a=−6 m/s

2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+

2

1

at

2

s=12×2+

2

1

×(−6)×4

⇒s=12 m

Explanation:

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