Question

the break even point of the demand and supply functions D=1-2p-p² S=p²+p-1 is​

Answer 1

Answer:

D = S

$1 - 2p - {p}^{2} = {p}^{2} + p - 1 \\ {2p}^{2} + 3p - 2 = 0 \\ {2p}^{2} + 4p - p - 2 = 0 \\ 2p(p + 2) - 1(p + 2) = 0 \\ (p + 2)(2p - 1) = 0 \\ p = - \frac{1}{2}$

Answer 2

Answer:

above answer is definitely correct