The breaking force needed to bring the car of maas 1200 kg to rest in 5 second. What it is moving at 20 m/s?
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Answer:
-4800 Newtons
Explanation:
Given :
- Initial velocity = u = 20 m/s
- Final velocity = v = 0 m/s
- Time taken = t = 5 seconds
- Mass of the car = m = 1200 kg
To find :
- The breaking force required to stop the car
Force = Mass×Acceleration
Acceleration = (v-u) /t
So force can be rewritten as :
Force = mass(final velocity - Initial velocity) / time
Force = 1200(0-20)/5
Force = 1200(-20)/5
Force = - 24000/5
Force = - 4800 Newtons
The breaking force required to stop the moving car at a velocity of 20 m/s to 0 m/s is equal to -4800 Newtons
NOTE : the force is negative as it is in the direction of movement of car
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