Question

The breaking strength of a steel cable is 20kN. If one pulls horizontal with this cable, what is the maximum horizontal acceleration which can be given to an 8 ton metric body resting on a rough horizontal surface if the coefficient of kinetic is 0.15?

Answer 1

Given:

Breaking strength of steel = 20 kN

Mass of the body = 8 tons

Coefficient of kinetic friction = 0.15

To find:

Maximum horizontal acceleration.

Solution:

Let the maximum horizontal acceleration be a.

The weight of the body = 8000*10 N

Frictional force = 0.15*80000 = 12000 N

The equation will be:

m*a = Tmax - frictional force

Tmax is the braking strength

m is the mass of the body

8000*a = 20000 - 12000

8000*a = 8000

a = 1 m/s²

Therefore, the maximum horizontal acceleration is 1 m/s².

Answer 2

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