Question

the breaking strength of the cable used to pull a body is 40N a body of mass 8kg is resting on a table of u= 0.20 the maximum acceleration which can be produced by the cable is ( Taking g=10 m/s-2).
PLEASE PLEASE PLEASE PLEASE PLEASE ANSWER.​

Answer 1

Answer:

Here breaking strength stands for maximum tension. So here for maximum acceleration T-fs = ma. 40-0.20×80=8a.a=3 m/ s^2.