The breaking strength of the table used to pull a body is 40 N. A body of mass 8 kg is resting on a table of the coefficient of friction μ=0.20 What is the maximum acceleration which can be produced by the table?
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Answer:
3m/s
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Explanation:
40N = 8*0.20 = 0.16.
N = 40/0.16 = 40*100/0.16*100 = 250*5dyne = 250*5*10^5 = 125*10^6.
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