the breaking stress of a material is 10^8 Nm^-2 .find the greatest lenght of a wire that could hang vertically without breaking.density of material=3000kgm^-3.
Class 11
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stress due to it's weight = Weight/Area
= W/A______[1]
W=mg= 9.8m ________[2]
also Area = volume/lenght
= (mass/density)/Lenght
= m/pL where p is density
given p = 3000 kgm^-3
so A = m/3000L_______[3]
from eqn 1,2 and 3
stress= 9.8m/(m/3000L)= 10^8
L= 10^8/29400 = 3401.36 m
= W/A______[1]
W=mg= 9.8m ________[2]
also Area = volume/lenght
= (mass/density)/Lenght
= m/pL where p is density
given p = 3000 kgm^-3
so A = m/3000L_______[3]
from eqn 1,2 and 3
stress= 9.8m/(m/3000L)= 10^8
L= 10^8/29400 = 3401.36 m
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