The breaking stress of aluminium is 7.5 into 10 to the power 7 newton per metre square find the greatest length of aluminium wire that can hang vertically without breaking density of aluminium is 2.7 into 10 to the power 3 kg per metre cube
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Answer:
Breaking stress of = σ=7.5x 10⁷ N/m2
density of Aluminium= ρ =2.7 X 103 kg/m3
g=10m/s²
let the maximum length that can be hung vertically be L
Let CSA=A
volume of wire=AL
mass of wire=ρAL
when hung force acting on the wire
F=ρALg
F/A=ρlg
σ= ρlg
now maximum, stress that wire can withstand σ=σb
so,
ρLg=σb =7.5x 10⁷
L=7.5x 10⁷/ρg
=7.5x 10⁷/2.7x10³x10
L=2.77x10³ m
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