Question

The breaks applied to a car produce an accelation of 6meter second square in opposit derction of motion if the car takes 2second to stop calculate the distance it travell during the time

Answer 1

acceleration = velocity/time
6 = velocity/2
velocity= 12

velocity = displacement/time
12=displacement/2
displacement=24m

Answer 2

Given a = - 6 m/s^2
V= 0 m/s
t = 2 secs
u = ?
S = ?
Applying first eqn of motion we get
V = u +at
0 = u + (-6)2
0=u-12
U= 12 m / s.
Now applying second equation we can get the distance car traves before coming to the rest.
S= ut + 1/2 at^2
S = 12×2 + 1/2 (-6)(2)(2)
S= 24-12
S = 12 meters .
Therefore car travels 12 metres before coming to rest.