The breaks applied to a car produce an acceleration of 6m/s square in the opposite direction of motion if the car takes 2sto stop after the application of brakes calculate the distance travelled by the car during this time
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Step-by-step explanation:
Given,
Acceleration, a = -6 m/s²
Time taken, t = 2 s
Final velocity, v = 0 m/s (As it stops.)
To Find,
Distance travelled, s = ?
Formula to be used,
1st equation of motion, v = u + at
2nd equation of motion, s = ut + 1/2 at²
Solution,
Putting all the values, we get
v = u + at
⇒ 0 = u + (- 6) × 2
⇒ u = 12 m/s
Here, the initial velocity is 12 m/s.
Now, the distance travelled,
s = ut + 1/2 at²
⇒ s = 12 × 2 + 1/2 × (- 6) × 2²
⇒ s = 24 - 12
⇒ s = 12 m
Hence,the distance travelled is 12 m.
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