the breaks applied to a scooter produces a retardation of 6m/s square . if the scooter takes 2 seconds to stop applying the breaks the distance it covers during the time is
Answers
Answered by
9
Answer:
s=(u*t)-1/2(a*t^2)
the answer will be 12 mts
Answered by
2
Answer:
s=(u*t)-1/2(a*t^2)
the answer will be 12 mts
Explanation:
Similar questions