Question

the breaks applied to a scooter produces a retardation of 6m/s square . if the scooter takes 2 seconds to stop applying the breaks the distance it covers during the time is​

Answer 1

Answer:

s=(u*t)-1/2(a*t^2)

the answer will be 12 mts

Answer 2

Answer:

s=(u*t)-1/2(a*t^2)

the answer will be 12 mts

Explanation: