Math, asked by anuraggmailcom7185, 7 months ago

The breath of a rectangle is 3cm longer than its length if the area is 180 find the dimension of the rectangle

Answers

Answered by sethrollins13
14

Given :

  • Breadth of Rectangle is 3 cm longer than its Length .
  • Area of Rectangle is 180 cm² .

To Find :

  • Dimensions of Rectangle .

Solution :

\longmapsto\tt{Let\:Length\:be=x}

As Given that Breadth of Rectangle is 3 cm longer than its length . So ,

\longmapsto\tt{Breadth=x+3}

Using Formula :

\longmapsto\tt\boxed{Area\:of\:Rectangle=length\times{breadth}}

Putting Values :

\longmapsto\tt{180=x\times{x+3}}

\longmapsto\tt{180={x}^{2}+3}

Now ,

\longmapsto\tt{{x}^{2}+3-180}

By Splitting Middle Term :

\longmapsto\tt{{x}^{2}+(15x-12x)-180}

\longmapsto\tt{{x}^{2}+15x-12x-180}

\longmapsto\tt{x(x+15)-12(x+15)}

\longmapsto\tt{(x-12)\:\:(x+15)}

  • x = 12
  • x = -15

As Dimensions can not be negative .So , The Value of x is 12 ...

Therefore :

\longmapsto\tt\bf{Length=12\:cm}

\longmapsto\tt{Breadth=12+3}

\longmapsto\tt\bf{15\:cm}

Answered by sk181231
35

Answer:

\sf\bold\red{AnswEr}

Given :

  • Breadth of rectangle is 3cm longer than the length .
  • Area of rectangle is 180m² .

To find :

  • Dimensions of rectangle

Solution :

Let , length of rectangle be x .

As given ,that breadth is 3cm longer than its length . So ,

\sf{ Breadth = x + 3}

Using formula :

\red{\boxed{\ Area \: of\: rectangle = Length × Breadth }}

Putting values :

\sf{➙ 180 = x × x + 3}

\sf{➙ 180 = x² + 3}

Now :

\sf{➙ x² + 3 - 189}

By splitting middle term :

\sf{➙ x² + ( 15x - 12x ) - 180}

\sf{ ➙ x² + 15x - 12x - 180}

\sf{➙  x ( x + 15 ) - 12 ( x + 15 )}

\sf{ ( x - 12 ) ( x + 15 ) }

  • x = 12
  • x = -15

As dimensions can not be negative .So , the value of x is 12.

Therefore :

  • Length = 12cm
  • Breadth = 12 + 3

\sf{➙ 15 }

Hence , Breadth of rectangle is 15 cm .

Similar questions