Question

the breath of a rectangular park is 7m less than its length. if the perimeter of the park is 1034 m, find the dimension of the park.

Answer 1

HEYA!!
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Let the Length of the Park be X m

Then Breadth of the park = ( X - 7 ) M

Perimeter of Rectangle = 2 × ( L + B )

Perimeter Given = 1034 m


So we have ,

2 × ( X + X - 7 ) = 1034

2 × ( 2X - 7 ) = 1034

(2X - 7 ) = 5 17

2X = 517 + 7

2X = 524

X = 262


〰Length of plot is 262 m

〰Breadth of plot is 255 m

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Answer 2

Let length be = x m

let breadth be = (x-7)m

Perimeter of a rectangle = 2(l + b)

1034=2 (x+(x-7))

1034= 2(x+x-7)

1034= 2(2x-7)

1034= 4x-28

1034+28=4x

1062=4x

1062/4=x

265.5m=x(length)

258.5m=x-7(breadth)

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