Question

the bredth of a rectangle is 15 m less than its length .the perimeter of a rectangle​

Answer 1

Step-by-step explanation:

Given,The breadth of a rectangle is 15m less than the length.

so let's assume,The measure of length of the rectangle to be x.

Then according to the problem,

The measure of breadth of the rectangle = x - 15.therefore,

The perimeter of rectangle is 2(l + b).

Since, here l = x , b= (x-15)

The perimeter of the rectangle= 2(x+x-15)

= 2(2x-15)

= (4x - 30)

so here The perimeter is (4x-30)m

Answer 2

$\huge \red{\mathfrak{solution}}$

Given:

◆ The breadth of a rectangle is 15m less than its length .

Let ,

•length = x m

and

•breadth=( x-15)m

To find :

◆ perimeter of rectangle =

$\blue{ \bold{ \boxed{2(l + b)}}}$

Now put value of Length and breadth ,

$\leadsto \: 2(x + x -1 5) \\ \\ \leadsto \: 2(2x - 15) \\ \\ \leadsto \: 4x - 30$

◆Hence, the perimeter of the rectangle is

$\purple{\boxed{ \bold{( {4x - 30} ) m}}}$