Math, asked by sanjanapramanik654, 14 hours ago

the brother is elder to his sister by 6 years. seven years ago the product of their ages was 72. what is the age of brother​

Answers

Answered by CuteAnswerer
20

GIVEN :

  • The brother is elder to his sister by 6 years.

  • Seven years ago, the product of brother's age and sister's age was 72.

TO FIND :

  • The Present Age Of Brother.

SOLUTION :

Let the present age of sister be x years.

  • Then, the present age of brother = (x+6) years

Seven Years Ago,

  • The age of sister = (x-7) years

  • The age of brother = (x+6-7) = (x-1) years

We know that,

  • Seven years ago, the product of brother's age and sister's age was 72.

According to the question :

\longmapsto \sf{Brother's  \: age \times Sister's\: age  = 72} \\  \\

\longmapsto \sf{(x - 1) (x -7) = 72 }\\  \\

\longmapsto \sf{x(x - 1) - 7(x -1)= 72 }\\  \\

\longmapsto \sf{ x^2- x- 7x  + 7 = 72} \\  \\

\longmapsto \sf{ x^2- 8x + 7 = 72} \\  \\

  • Transposing 72 to LHS by changing its sign.

\longmapsto \sf{ x^2- 8x   + 7 - 72=0} \\  \\

\longmapsto \sf{ x^2- 8x  - 65=0} \\  \\

\longmapsto \sf{ x^2 + 5x  -13x -  65=0} \\  \\

  • Middle term splitting.

\longmapsto\sf{ x(x + 5)  -13(x + 5 )=0} \\  \\

\longmapsto\sf{ (x + 5) (x  - 13 )=0} \\  \\

\longmapsto\sf{ (x + 5)  = 0 \: , \: (x  - 13 )=0}\\  \\

\longmapsto\sf{ x  = 0  - 5\: , \: x =0 + 13}\\  \\

\longmapsto\bf{ x  = - 5\: , \: x = 13}

  • Age can't be negative.

The Present Age Of Sister :

  • x years = 13 years

The Present Age of Brother :

  • (x+6) years = 13+6 = 19 years

  • Final Answer :

\huge{\blue{\therefore}} The Present Age Of Brother is 19 years.


Swarup1998: Nice work!
mddilshad11ab: Perfect explaination ✔️
MisterIncredible: Too good !
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