The brown ring complex compound is formulated as [Fe(H2O)5 NO]SO4. The oxidation state of iron is
a) +1
b) +2
c) +3
d) +6
Answers
The oxidation number of iron in the above compound can be calculate as follow:
[Fe(NO)(H2O)5]SO4 dissociate in water to liberate [Fe(NO)(H2O)5]2+ ions and SO42- ions.
The charge on NO is +1 i.e. NO+, whereas H2O ligand is neutral.
Hence the oxidation state of iron in above complex is
X + (+1) +5(0) = +2
⇒ X = +1
Therefore, iron is present in +1 oxidation state in the above complex.
Answer:
Explanation:
The oxidation number of iron in the above compound can be calculate as follow:
[Fe(NO)(H2O)5]SO4 dissociate in water to liberate [Fe(NO)(H2O)5]2+ ions and SO42- ions.
The charge on NO is +1 i.e. NO+, whereas H2O ligand is neutral.
Hence the oxidation state of iron in above complex is
X + (+1) +5(0) = +2
⇒ X = +1
Therefore, iron is present in +1 oxidation state in the above complex.