Question

The bulb L1 in the circuit blows out. Find the current through bulb 2 and calculate its voltage.
The battery applied is of voltage 9V.

Answer 1

Answer:

0

Explanation:

the bulb l1 in the circuit blows out find the current through bulb 2and calculate its voltage

Answer 2

The bulb L1 in the circuit blows out, 7 ampere is  the current through bulb 2 and its voltage.

• Power is the critical factor for the capacitor and resistance.
• The standard power unit is the watt; sometimes, it is measured in joules.
• Power is nothing but, it is the charge of the electric current.
• It is done between intervals of time.
• The power is the capacity of the work done.
• Energy applies to the fact of the momentum of energy.
• In that case, the well-known factor is that energy is not to be created nor to be destroyed.
• Energy is measured in the standard unit of a joule.
• The energy is to be indifferent they are chemical energy, electrical energy and light energy.
• The energy formula was invented by Albert Einstein.
• Energy is done by the form of motion.
• Energy falls under the scalar quantity.
• Parallel Circuit
• Because all have higher voltage across them.
• Series Circuit
• Because if one bulb goes out, the current won't reach the next bulb.

Therefore, bulb L1 in the circuit blows out, 7 ampere is  the current through bulb 2 and its voltage.

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