Physics, asked by yasmeen786, 11 months ago

the bulk modulus of copper is 138 into 10 ki power 9 Pascal the additional pressure generated and expansion chamber this 345 into 10 ki power 6 Pascal the percentage in the volume of piece of copper plates the Chamber will be​

Answers

Answered by abhi178
13

the bulk modulus of copper is 138 × 10^9 Pascal the additional pressure generated and expansion chamber this 345 × 10^6 Pascal the percentage in the volume of piece of copper plates the Chamber will be

we know, bulk modulus = P/(∆V/V)

given, bulk modulus = 138 × 10^9 Pa

pressure, P = 345 × 10^6 Pa

now, 138 × 10^9 = 345 × 10^6/(∆V/V)

⇒∆V/V = 345 × 10^6/(138 × 10^9)

= 2.5 × 10^-3

so, % change in volume of copper plate = ∆V/V × 100 = 2.5 × 10^-3 × 100 = 0.25 %

Answered by Anonymous
5

\huge\bold\purple{Answer:-}

the bulk modulus of copper is 138 × 10^9 Pascal the additional pressure generated and expansion chamber this 345 × 10^6 Pascal the percentage in the volume of piece of copper plates the Chamber will be

we know, bulk modulus = P/(∆V/V)

given, bulk modulus = 138 × 10^9 Pa

pressure, P = 345 × 10^6 Pa

now, 138 × 10^9 = 345 × 10^6/(∆V/V)

⇒∆V/V = 345 × 10^6/(138 × 10^9)

= 2.5 × 10^-3

so, % change in volume of copper plate = ∆V/V × 100 = 2.5 × 10^-3 × 100 = 0.25 %

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