Question

The bulk modulus of water is 2.0xx10^(9) N//m^(2). The pressure required to increase the density of water by 0.1% is

Answer 1

Answer:

2 × 10 ^6

Explanation:

hope the answer will help you

Answer 2

The pressure required to increase the density of water by 0.1% is $2 \times 10^{6}$ Pa.

Explanation:

Given :

Bulk modulus of water $K = 2 \times 10^{9}$ $\frac{N}{m^{2} }$

From the formula of bulk modulus,

   $K = \frac{\Delta P}{\frac{\Delta V}{V} }$

Here in our case density is increase 0.1% so volume decrease 0.1%

because density is inversely proportional to the volume,

So   $\frac{\Delta V}{V} = 0.1 \%$

Writing for increase in pressure,

 $\Delta P = K \frac{\Delta V}{V}$

 $\Delta P = 2 \times 10^{9} \times 0.001$

 $\Delta P = 2 \times 10^{6}$ Pa