The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object.
What is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm?
The iron has a mass of 213 g. Remember that water has a density of 1.00 g/cm3.
Hint: Determine the volume of the displaced water. Then determine the mass using your knowledge of the density of water. Finally, convert the mass to weight using Weight = mg, where mass is in kilograms and gravity, g = 9.80 m/s2.
265 N
27.0 g
2.76 g
0.265 N
Answers
Answer:he buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. What is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g. Remember that water has a density of 1.00 g/cm3.
To determine the weight of the displaced water, we need to know the volume of the block. Since the entire block is submerged, the volume of displaced water = volume of block!!
Volume of block = 3 * 3 * 3 = 27 cubic cm
Now we need to determine the weight of 27 cc of water.
Weight = mass in kg * 9.8
Density = mass / volume
1 g/cc = mass / 27
Mass = 27 g
Weight = mass in kg * 9.8
Mass in kg = 0.027 kg
Weight of block = 0.027 * 9.8 = 0.2646 N
The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object.
Buoyant force = 0.2646 N
a is incorrect, because force is weight, not mass
d is correct,
Explanation: