the bus fare in a city is as follows. For first 1 km the fare is ₹15 and for the subsequent distance, it is ₹8 /km. Taking distance covered as y km and the total fare as X , write the linear equation in the form of ac+by=c. If she covered 67km , then find the total fare.
Answers
Answer:
Given,Total distance covered= x
km=1+(x-1)km
Fare For first kilometre= ₹8
Fare for subsequent distance= ₹5 per km
Fare for next(x-1)km= 5(x-1)
A.T.Q
Total fare= y
8+5(x-1)=y
8+5x-5=y
5x-y+3=0
Which is the required linear equation.
It can also be written as y= 5x+3
When X = 0 ,then Y = 3,When x=1, then y=
5+3=8
When x= 2, then y= 10+3=13
[Table & graph are on the attachment]
Now plot the points A(0,3), B(1,8), C(
2,13) on the graph paper and join them to form a line BC, which represents the
required graph of linear equation.
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Hope this will help you.....
1km--15
snth=u+1/2 a (2n-1)
15=u+a/2 (2(1)-1)
15=u+a/2 (1)
15=2u+1a/2
30=2u+1a....eqn1
=8km---67
snth=u+1/2a (2n-1)
67=u+a/2(2(8)-1)
67=u+a/2 (15)
67=2u+15a
134=2u+15a....eqn2
substric eqn 1 & 2
134=2u+15a
30=2u+1a ans:: 104/14=a
ans:: 7.42