Question

the bus fare in a city is as follows for the first five kilometers the fare is as 10 and the subsequent distance is RS 2km. taking the distance x and total fare y write a linear equation what will be the bus fare at 10 km and 19km​

Answer 1

Explanation:

We require Unitary Method to solve the question.

Fare for first 5 km =₹2

Fare for 1 km = ₹2/5

Hence fare for 10 km = ₹4

Fare for 19 km = ₹2/5 ×19= ₹38/5

Hence equation is. 10x= y and 19x =y

Answer 2

Answer:

Rs.y= 5 x 10 + 2(x-5)

Rs.y=50 + 2x - 10 = 50-10+2x

Rs.y= 40 + 2x

i)x= 10km

=> y= 40+2(10) = 40+20=Rs.60

ii)x= 19km

=> y= 40+2(19) = 40 + 38 = Rs.78

Explanation:

x=distance

y=total price

in first step we have done 2(x-5) as Rs.2 is the subsequent charge and that is charged for the total distance - the first 5 km