Question

The bus moving with a speed of 42 km/h is brought to a stop by brakes after 6 m. If the same bus is moving
at a speed of 90 km/h, then the minimum stopping distance is

(1) 15.48 m
(2) 18.64 m
(3) 22.13 m
(4) 27.55 m​

Answer 1

Explanation:

the answer is 15.48m ... mark a brainlist

Answer 2

Answer:

(4) 27.55

Explaination:

for first case

u = 42km/h = 42*5/18 = 11.66

v = 0

s = 6m

v^2 = u^2 + 2as

(11.66)^2 = 0 + 2a*6

a= 11.33

for second case

u= 90 km/h = 25 m/s

v^2 = u^2 + 2as

s = 27.55 m

PLEASE MARK BRAINLIEST